Solve $2^{x} \cdot 2^{x+1} = 32$.

Solve $2^{x} \cdot 2^{x+1} = 32$.
  1. $1$
  2. $2$
  3. $3$
  4. $4$

Solution

Add exponents: $2^{2x+1} = 2^{5} \Rightarrow 2x + 1 = 5 \Rightarrow x = 2$.

Asked in: IMO

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