Solve by elimination: $2x + 3y = 13$ and $4x - y = 5$. Then $x$ is

Solve by elimination: $2x + 3y = 13$ and $4x - y = 5$. Then $x$ is
  1. $2$
  2. $3$
  3. $1$
  4. $4$

Solution

Multiply 2nd by $3$: $12x - 3y = 15$. Add to first: $14x = 28 \Rightarrow x = 2$.

Asked in: MH-SSC-9

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