$\mathrm{FeCl}_{3}$ solution on reaction with $\mathrm{SO}_{2}$ changes to
- $\mathrm{FeCl}_{2}$
- $\mathrm{Fe}_{2}\left(\mathrm{SO}_{4}ight)_{3}$
- $\mathrm{Fe}_{2}\left(\mathrm{SO}_{3}ight)_{3}$
- $\mathrm{FeSO}_{4}$
Solution
,Asked in: JEE-TOPICTESTS-CHEMISTRY
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