Sodium borate on reaction with conc. \(\mathrm{H}_{2} \mathrm{~S} \mathrm{O}_{4}\) and \(\mathrm{C}_{2}…
- \(\mathrm{H}_{2} \mathrm{Bu} \mathrm{O}_{7}\)
- \(\left(\mathrm{C}_{2} \mathrm{H}_{5}ight)_{2}\mathrm{~B}_{4} \mathrm{O}_{7}\)
- \(\mathrm{H}_{3} \mathrm{BO}_{3}\)
- \(\left(\mathrm{C}_{2} \mathrm{H}_{5}ight)_{3} \mathrm{BO}_{3}\)
Solution
\(\mathrm{H}_{3} \mathrm{BO}_{3}+3 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \longrightarrow \left(\mathrm{C}_{2} \mathrm{H}_{5}ight)_{3} \mathrm{BO}_{3} \text { or }\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}ight)_{3} \mathrm{~B}\)
Asked in: JEE-TOPICTESTS-CHEMISTRY