Sodium acetate was electrolysed by Kolbe's method to form two gases $A$ and $B$ at anode. $C$ and $D$ are formed, when $B$ is heated with regulated supply of $\mathrm{O}_2$ or air in the presence of $\left(\mathrm{CH}_3 \mathrm{COO}\right)_2 \mathrm{Mn}$. $\mathrm{C}$ reacts with…

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Sodium acetate was electrolysed by Kolbe's method to form two gases $A$ and $B$ at anode. $C$ and $D$ are formed, when $B$ is heated with regulated supply of $\mathrm{O}_2$ or air in the presence of $\left(\mathrm{CH}_3 \mathrm{COO}\right)_2 \mathrm{Mn}$. $\mathrm{C}$ reacts with $\mathrm{NaOH}$ to form a salt. $A$ and $D$ are respectively,

Aicharya · Accepted Answer

Kolbe electrolysis of $\mathrm{CH}_3 \mathrm{COO}^{-} \mathrm{Na}^{+}$. At anode, $\begin{aligned} & \mathrm{CH}_{3}^{*}+\mathrm{CH}_{3}^{*} \longrightarrow \mathrm{CH}_{3} \underset{(\mathrm{A})}{-\mathrm{CH}_{3}} \ & 2 \mathrm{CH}_{3}-\mathrm{CH}_{3}+7 \mathrm{O}_{2} \stackrel{\left(\mathrm{CH}_{3} \mathrm{COO}_{2} \mathrm{Mn}\right)}{\longrightarrow} 4 \mathrm{CO}_{2}+\underset{\mathrm{(D)}}{6 \mathrm{H}_{2} \mathrm{O}} \end{aligned}$ $ \mathrm{CO}_{2}+\mathrm{O}_{2} \longrightarrow \underset{\mathrm{(C)}}{\mathrm{CO}}+\mathrm{O}_{3} \mathrm{CO}+\mathrm{NaOH} \rightleftharpoons \underset{\text{(Salt)}}{\mathrm{HCOONa}} $ Hence, $A$ is $\mathrm{C}_{2} \mathrm{H}_{6}$ and $D$ is $\mathrm{H}_{2} \mathrm{O}$.

Sodium acetate was electrolysed by Kolbe's method to form two gases \(A\) and \(B\) at anode. \(C\) and…

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