Smallest of $\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}, \dfrac{1}{6}$ is
Smallest of $\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}, \dfrac{1}{6}$ is
- $\dfrac{1}{6}$
- $\dfrac{1}{4}$
- $\dfrac{1}{3}$
- $\dfrac{1}{2}$
Solution
Larger denominator $\Rightarrow$ smaller value.
Asked in: NSO
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