' $n$ ' small drops of same size are charged to 'V' volt each. If they coalesce to form a single large drop, then its potential will be

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Aicharya · Accepted Answer

$\mathrm{V}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}}{\mathrm{r}}$ $\begin{aligned} \mathrm{V}^{\prime} & =\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}^{\prime}}{\mathrm{r}^{\prime}} \ & =\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{nq}}{\mathrm{n}^{1 / 3} \mathrm{r}} \quad\left(\because \mathrm{q}^{\prime}=\mathrm{nq}, \mathrm{r}^{\prime}=\mathrm{n}^{1 / 3} \mathrm{r}ight) \ \mathrm{V}^{\prime} & =\mathrm{Vn}^{2 / 3}\end{aligned}$

' $n$ ' small drops of same size are charged to 'V' volt each. If they coalesce to form a single large drop,…

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