Six equal resistances are connected between points $\mathrm{P}, \mathrm{Q}$ and $\mathrm{R}$ as shown in…

Six equal resistances are connected between points $\mathrm{P}, \mathrm{Q}$ and $\mathrm{R}$ as shown in figure. Then net resistance will be maximum between :
  1. $\mathrm{P}$ and $\mathrm{R}$
  2. P and Q
  3. Q and R
  4. Any two points

Solution

Resistance between $\mathrm{P}$ and $\mathrm{Q}$ $ r_{\mathrm{PQ}}=r_{11}\left(\frac{r}{3}+\frac{r}{2}\right)=\frac{r \times \frac{5}{6} r}{r+\frac{5}{6} r}=\frac{5}{11} r $ Resistance between Q and R $ \mathrm{r}_{\mathrm{QR}}=\frac{\mathrm{r}}{2} 11\left(\mathrm{r}+\frac{\mathrm{r}}{3}\right)=\frac{\frac{\mathrm{r}}{2} \times \frac{4}{3} \mathrm{r}}{\frac{\mathrm{r}}{2}+\frac{4}{3} \mathrm{r}}=\frac{4}{11} \mathrm{r} $ Resistance between $\mathrm{P}$ and $\mathrm{R}$ $ \mathrm{r}_{\mathrm{PR}}=\frac{\mathrm{r}}{3} \mathrm{l}\left(\frac{\mathrm{r}}{2}+\mathrm{r}\right)=\frac{\frac{\mathrm{r}}{3} \times \frac{3}{2} \mathrm{r}}{\frac{\mathrm{r}}{3}+\frac{3}{2} \mathrm{r}}=\frac{3}{11} \mathrm{r} $ Hence, it is clear that $\mathrm{r}_{\mathrm{PQ}}$ is maximum

Asked in: JEE Main 2013 (25 Apr Online)

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