Simplify $\dfrac{6^{n+1} \cdot 6^{n-1}}{6^{2n-1}}$.

Simplify $\dfrac{6^{n+1} \cdot 6^{n-1}}{6^{2n-1}}$.
  1. $1$
  2. $6$
  3. $36$
  4. $6^{n}$

Solution

$6^{(n+1)+(n-1)-(2n-1)} = 6^{1} = 6$.

Asked in: IMO

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