Simplify $\dfrac{4^{3} \cdot 9^{2}}{6^{4}}$.

Question

Aicharya · Accepted Answer

Express each base in primes: $\dfrac{(2^{2})^{3} \cdot (3^{2})^{2}}{(2 \cdot 3)^{4}} = \dfrac{2^{6} \cdot 3^{4}}{2^{4} \cdot 3^{4}} = 2^{2} = 4$.

Solution