Simplify $4^{3} \cdot 4^{2} \div 4^{4}$.

Simplify $4^{3} \cdot 4^{2} \div 4^{4}$.
  1. $4^{1} = 4$
  2. $4^{9}$
  3. $4^{2}$
  4. $4^{-1}$

Solution

$4^{3+2-4} = 4^{1} = 4$.

Asked in: NTSE-F

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