Simplify $(2^{3})^{4} \cdot 2^{-7}$.

Simplify $(2^{3})^{4} \cdot 2^{-7}$.
  1. $2^{5} = 32$
  2. $2^{19}$
  3. $2^{-1}$
  4. $2^{0} = 1$

Solution

$(2^{3})^{4} = 2^{12}$. Then $2^{12} \cdot 2^{-7} = 2^{12-7} = 2^{5} = 32$.

Asked in: IMO

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