Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of $M^{+ n}$ ion are provided below; their $λ_{\max}$ values are marked as $A, B$ and $C$ respectively. The correct match between the complexes and their $λ_{\max}$ values is:
(i) ${[M (NCS)_{6}]}^{(- 6 + n)}$
(ii) ${[{MF}_{6}]}^{(- 6 + n)}$
(iii) ${[M {({NH}_{3})}_{6}]}^{n +}$

Question

Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of $M^{+ n}$ ion are provided below; their $λ_{\max}$ values are marked as $A, B$ and $C$ respectively. The correct match between the complexes and their $λ_{\max}$ values is:

(i) ${[M (NCS)_{6}]}^{(- 6 + n)}$
(ii) ${[{MF}_{6}]}^{(- 6 + n)}$
(iii) ${[M {({NH}_{3})}_{6}]}^{n +}$

Aicharya · Accepted Answer

Stronger the ligand greater is splitting of d orbitals and smaller will be wave length of light absorbed.
The splitting power of ligands is

{NH}_{3} > {NCS}^{-} > F^{-}

So order of wave length of light absorbed is

λ_{{NH}_{3}} < λ_{NC \bar{S}} < λ_{F^{-}}

Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of M + n ion are provided below;…

Solution