Silicon (IV) chloride on hydrolysis gives an acid $X$. The number of $-\mathrm{OH}$ groups present in $X$ is

Silicon (IV) chloride on hydrolysis gives an acid $X$. The number of $-\mathrm{OH}$ groups present in $X$ is
  1. $2$
  2. $3$
  3. $6$
  4. $4$

Solution

Silicon (IV) chloride on hydrolysis gives silicic acid. The reaction involve is as follows.
Thus, the number $-\mathrm{OH}$ groups present is 4 .

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

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