Side of rhombus with diagonals $6$ and $8$ is
Side of rhombus with diagonals $6$ and $8$ is
- $5$
- $7$
- $10$
- $\sqrt{14}$
Solution
Half-diagonals are legs: $\sqrt{3^2+4^2} = \sqrt{25} = 5$.
Asked in: MH-SSC-9
Practice more Quadrilaterals questions on Aicharya