\(\mathrm{SF}_6\) is a kinetically inert substance because

\(\mathrm{SF}_6\) is a kinetically inert substance because
  1. fluorine is highly electronegative
  2. it is sterically protected
  3. greater difference in electronegativities of \(\mathrm{S}\) and \(\mathrm{F}\)
  4. larger size of S-atom

Solution

In \(\mathrm{SF}_6\), sulphur is \(s p^3 d^2\) hybridised. Both geometry and shape of the molecule is octahedral. \(\mathrm{SF}_6\) is also a non-polar molecule (dipole moment, \(\mu=0\) ), because if \(a^{-}\)and sterically protected perfectly symmetrical molecule. So, \(\mathrm{SF}_6\) is also kinetically inert.

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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