Sequence of acidic character is
- $\mathrm{N}_{2} \mathrm{O}_{5}>\mathrm{SO}_{2}>\mathrm{CO}>\mathrm{CO}_{2}$
- $\mathrm{N}_{2} \mathrm{O}_{5}>\mathrm{SO}_{2}>\mathrm{CO}_{2}>\mathrm{CO}$
- $\mathrm{SO}_{2}>\mathrm{CO}_{2}>\mathrm{CO}>\mathrm{N}_{2} \mathrm{O}_{5}$
- $\mathrm{SO}_{2}>\mathrm{N}_{2} \mathrm{O}_{5}>\mathrm{CO}>\mathrm{CO}_{2}$
Solution
oxide of nitrogen $>$ oxides of sulfur $>$ oxides of carbon. Among oxides of carbon acidic character increases with
the oxidation number of carbon. So, ${ }^{+4} \mathrm{CO}_{2}$ is more acidic than CO. Hence the sequence of acidic character is $\mathrm{N}_{2} \mathrm{O}_{5}$ $>\mathrm{SO}_{2}>\mathrm{CO}_{2}>\mathrm{CO}$ *
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