Scalar projection of the line segment joining the points $\mathrm{A}(-2,0,3), \mathrm{B}(1,4,2)$ on the line…
Scalar projection of the line segment joining the points $\mathrm{A}(-2,0,3), \mathrm{B}(1,4,2)$ on the line whose direction ratios are $6,-2,3$ is
- $\frac{23}{7}$
- 1
- 7
- $\frac{1}{7}$
Solution
Let $\bar{a}$ be the vector joining $\mathrm{A}(-2,0,3)$ and $\mathrm{B}(1,4,2)$.
$\begin{aligned}
& \therefore \quad \overline{\mathrm{a}}=(1-(-2)) \hat{\mathrm{i}}+(4-0) \hat{\mathrm{j}}+(2-3) \hat{\mathrm{k}} \\
& =3 \hat{i}+4 \hat{j}-\hat{k} \\
& \text { and } \bar{b}=6 \hat{i}-2 \hat{j}+3 \hat{k} \\
& \therefore \quad \text { Projection }=\frac{\overline{\mathrm{a}} \cdot \overline{\mathrm{b}}}{|\overline{\mathrm{b}}|}=\frac{3 \times 6+4 \times(-2)-1 \times 3}{\sqrt{6^2+(-2)^2+3^2}} \\
& =\frac{18-8-3}{\sqrt{49}} \\
& =\frac{7}{7} \\
& =1 \\
&
\end{aligned}$
Asked in: MHT CET 2023 (10 May Shift 1)
Practice more Vectors questions on Aicharya