Sand is being dropped on a conveyor belt at the rate of $\mathrm{M} \mathrm{kg} / \mathrm{s}$. The force…

Sand is being dropped on a conveyor belt at the rate of $\mathrm{M} \mathrm{kg} / \mathrm{s}$. The force necessary to keep the belt moving with a constant velocity of $v \mathrm{~m} / \mathrm{s}$ will be
  1. Zero
  2. $\mathrm{M} v$ newton
  3. $2 \mathrm{M} v$ newton
  4. $\frac{M v}{2}$ newton

Solution

Force $=v \frac{d u}{d t}=M v$

Asked in: NEET 2008 (Mains)

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