Same quantity of electricity was passed through solutions of sales of elements $X, Y$ and $Z$ with atomic…
Same quantity of electricity was passed through solutions of sales of elements $X, Y$ and $Z$ with atomic masses 7,27 and 48 respectively. The mass of $X, Y$ and $Z$ deposited were $2.1 \mathrm{~g}, 2.7 \mathrm{~g}$ and $7.2 \mathrm{~g}$ respectively. The valence's of $X, Y$ and $Z$ respectively are
3,2 and 1
1,2 and 3
1,3 and 2
2,3 and 1
Solution
According to Faraday's law
$
\begin{array}{rlr}
W & =Z Q & {[W=\text { weight of substance }]} \\
& =\frac{E Q}{96500} \quad[E=\text { Equivalent weight }]
\end{array}
$
For $X$
$
2.1=\frac{(7 / x) Q}{96500}
$
For $Y$
$
2.7=\frac{(27 / y) Q}{96500}
$
For $Z$
$
\begin{aligned}
7.2 & =\frac{(48 / z) Q}{96500} \\
x: y: z & =\left(\frac{7}{2.1}\right):\left(\frac{27}{2.7}\right):\left(\frac{48}{7.2}\right) \\
& =3.33: 10: 6.66 \simeq 1: 3: 2
\end{aligned}
$