Resistances in the left gap and right gap of a meter bridge are $10 \Omega$ and $30 \Omega$ respectively. If the resistances in the two gaps are interchanged, the balance point will shift to right by

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Aicharya · Accepted Answer

In first case $\begin{aligned} & \mathrm{R}=10 \Omega \quad \mathrm{~S}=30 \Omega \\ & \frac{\mathrm{R}}{\mathrm{~S}}=\frac{l}{100-l} \\ & \frac{10}{30}=\frac{l}{100-l} \\ & l_1=25 \mathrm{~cm} \end{aligned}$
In second case $\begin{aligned} & \mathrm{R}=30 \Omega ; \quad \mathrm{S}=10 \Omega \\ & \frac{\mathrm{R}}{\mathrm{~S}}=\frac{l^{\prime}}{100-l^{\prime}} \\ & \frac{30}{10}=\frac{l^{\prime}}{100-l^{\prime}} \\ & l^{\prime}=75 \mathrm{~cm} \end{aligned}$ $\therefore \quad$ The balance point will shift by $75 \mathrm{~cm}-25 \mathrm{~cm}$ is 50 cm

Resistances in the left gap and right gap of a meter bridge are $10 \Omega$ and $30 \Omega$ respectively. If…

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