Resistance and conductivity of a cell containing 0.1 M KCl solution at 298 K are 115 ohm and $1.90 imes 10^{-6} \mathrm{~S} \mathrm{~cm}^{-1}$ respectively. What is the value of cell constant?

Question

Resistance and conductivity of a cell containing 0.1 M KCl solution at 298 K are 115 ohm and $1.90 	imes 10^{-6} \mathrm{~S} \mathrm{~cm}^{-1}$ respectively. What is the value of cell constant?

Aicharya · Accepted Answer

- Resistance: 115 ohm - Conductivity: $1.90 \times 10^{-6} \mathrm{~S} \mathrm{~cm}^{-1}$ - Formula to find the cell constant $\left(\frac{l}{a}\right)$ : $\frac{l}{a}=k \times R$ where $k$ is the conductivity and $R$ is the resistance.
Given Data: - $k=1.90 \times 10^{-6} S^{-1}$ - $R=115 \Omega$
Calculation: Substituting the given values into the formula: $\frac{l}{a}=\left(1.90 \times 10^{-6}\right) \times 115=0.2185 \mathrm{~cm}^{-1}$
Answer: The cell constant is approximately $0.2185 \mathrm{~cm}^{-1}$, which matches with Option 4: $0.218 \mathrm{~cm}^{-1}$.

Resistance and conductivity of a cell containing 0.1 M KCl solution at 298 K are 115 ohm and $1.90 \times…

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