Remainder when $x^{3} + 1$ is divided by $(x + 1)$ is

Remainder when $x^{3} + 1$ is divided by $(x + 1)$ is
  1. $0$
  2. $1$
  3. $-1$
  4. $2$

Solution

$p(-1) = -1 + 1 = 0$, so $(x+1)$ is a factor.

Asked in: MH-SSC-9

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