Remainder when $p(x) = x^{4} + x^{3} - 2x^{2} + x + 1$ is divided by $(x - 1)$ is

Remainder when $p(x) = x^{4} + x^{3} - 2x^{2} + x + 1$ is divided by $(x - 1)$ is
  1. $2$
  2. $1$
  3. $0$
  4. $-1$

Solution

$p(1) = 1 + 1 - 2 + 1 + 1 = 2$.

Asked in: MH-SSC-9

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