Remainder when $p(x) = x^{3} - 3x^{2} + 4x - 4$ is divided by $(x - 2)$ is

Remainder when $p(x) = x^{3} - 3x^{2} + 4x - 4$ is divided by $(x - 2)$ is
  1. $0$
  2. $4$
  3. $-4$
  4. $2$

Solution

$p(2) = 8 - 12 + 8 - 4 = 0$.

Asked in: MH-SSC-9

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