Remainder when $p(x) = x^{2} + 2x + 3$ is divided by $(x - 1)$ is

Remainder when $p(x) = x^{2} + 2x + 3$ is divided by $(x - 1)$ is
  1. $6$
  2. $3$
  3. $0$
  4. $-6$

Solution

$p(1) = 1 + 2 + 3 = 6$.

Asked in: MH-SSC-9

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