$\mathrm{P}_{4} \mathrm{O}_{10}$ reacts with water to produce
- $\mathrm{H}_{3} \mathrm{P}(\mathrm{OH})_{3}$
- $\mathrm{H}_{3} \mathrm{PO}_{3}$
- $\mathrm{H}_{3} \mathrm{PO}_{4}$
- $\mathrm{H}_{4} \mathrm{P}(\mathrm{OH})_{3}$
Solution
Asked in: MHT CET 2020 (14 Oct Shift 2)
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