$\mathrm{KO}_2$, reacts with water to form $A, B$ and $C$. $B$ forms $C$ when it reacts with iodine in basic medium. What are $B$ and $C$ respectively?

Question

Aicharya · Accepted Answer

(i) When $\mathrm{KO}_2$ reacts with water, it gives $(A)$, $(B)$ and $(C)$ as follows:

(ii) When $(B)$, i.e. $\mathrm{H}_2 \mathrm{O}_2$ reacts with iodine in basic medium, it gives $(C)$, i.e. $\mathrm{O}_2$, as shown below :

$\because \mathrm{KOH}$ can not reduce $\mathrm{I}_2$, thus option (d) is the correct answer.

$\mathrm{KO}_2$, reacts with water to form $A, B$ and $C$. $B$ forms $C$ when it reacts with iodine in basic…

Solution