$\mathrm{HBr}$ reacts with $\mathrm{CH}_2=\mathrm{CH}-\mathrm{OCH}_3$ under anhydrous conditions at room…

$\mathrm{HBr}$ reacts with $\mathrm{CH}_2=\mathrm{CH}-\mathrm{OCH}_3$ under anhydrous conditions at room temperature to give
  1. $\mathrm{CH}_3 \mathrm{CHO}$ and $\mathrm{CH}_3 \mathrm{Br}$
  2. $\mathrm{BrCH}_2 \mathrm{CHO}$ and $\mathrm{CH}_3 \mathrm{OH}$
  3. $\mathrm{BrCH}_2-\mathrm{CH}_2-\mathrm{OCH}_3$
  4. $\mathrm{H}_3 \mathrm{C}-\mathrm{CHBr}-\mathrm{OCH}_3$

Asked in: JEE Main 2006

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