$\mathrm{CuSO}_{4}$ reacts with excees $\mathrm{KCN}$ solution to form:

$\mathrm{CuSO}_{4}$ reacts with excees $\mathrm{KCN}$ solution to form:
  1. $\mathrm{Cu}(\mathrm{CN})$
  2. $\mathrm{Cu}(\mathrm{CN})_{2}$
  3. $\mathrm{K}_{3}\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]$
  4. $\mathrm{K}_{4}\left[\mathrm{Cu}(\mathrm{CN})_{6}ight]$

Solution

$2 \mathrm{CuSO}_{4}+10 \mathrm{KCN} \longrightarrow$
$2 \mathrm{~K}_{3}\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]+2 \mathrm{~K}_{2} \mathrm{SO}_{4}+(\mathrm{CN})_{2}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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