$\mathrm{HOCl}$ reacts on 3 -methyl-2-pentene, the main product will be :



- None of these
Solution
3 The reaction obeys Markovnikov's addition and the hydroxide and chloro group is added across the double bond of two carbons.
We can write the reaction of 3 -methyl-2-pentene with $\mathrm{HOCl}$ as,
,Asked in: JEE-TOPICTESTS-CHEMISTRY