Reaction of $\mathrm{Br}_2$ with $\mathrm{Na}_2 \mathrm{CO}_3$ in aqueous solution gives sodium bromide and…
Reaction of $\mathrm{Br}_2$ with $\mathrm{Na}_2 \mathrm{CO}_3$ in aqueous solution gives sodium bromide and sodium bromate with evolution of $\mathrm{CO}_2$ gas. The number of sodium bromide molecules involved in the balanced chemical equation is
Solution
$\mathrm{Br}_2$ is disproportionated in basic medium as
$
3 \mathrm{Br}_2+3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow 5 \mathrm{NaBr}+\mathrm{NaBrO}_3+3 \mathrm{CO}_2
$