Reaction of aniline with $\mathrm{HNO}_2$ followed by treatment of dilute acid gives
- $\mathrm{C}_6 \mathrm{H}_5 \mathrm{NHOH}$
- $\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}$
- $\mathrm{C}_6 \mathrm{H}_5 \mathrm{NHNH}_2$
- $\mathrm{C}_6 \mathrm{H}_6$
Asked in: NEET 2018