Rationalising factor of $\sqrt{a}$ is
Rationalising factor of $\sqrt{a}$ is
- $\sqrt{a}$
- $a$
- $\dfrac{1}{\sqrt{a}}$
- $a^{2}$
Solution
$\sqrt{a} \cdot \sqrt{a} = a$ (rational for rational $a$).
Asked in: MH-SSC-9
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