Ratio of thermal energy released in two resistor R and 3 R connected in parallel in an electric circuit is :

Ratio of thermal energy released in two resistor R and 3R connected in parallel in an electric circuit is :
  1. 3:1
  2. 1:1
  3. 1:3
  4. 1:27

Solution

In parallel connection, potential difference across resistors remains the same.

Thermal energy released in resistor is given by H=V2R×t

So, the ratio is H1H2=V2tRV2t3R=3RR=3:1.

Asked in: JEE Main 2023 (29 Jan Shift 1)

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