Radius of the first excited state of Helium ion is given as : $\mathrm{a}_0 \rightarrow$ radius of first…
Radius of the first excited state of Helium ion is given as :
$\mathrm{a}_0 \rightarrow$ radius of first stationary state of hydrogen atom.
- $\mathrm{r}=4 \mathrm{a}_0$
- $\mathrm{r}=2 \mathrm{a}_0$
- $r=\frac{a_0}{2}$
- $r=\frac{a_0}{4}$
Solution
$\begin{aligned} & \mathrm{r}=\mathrm{a}_0\left(\frac{\mathrm{n}^2}{\mathrm{z}}\right) \\ & \mathrm{r}=\frac{\mathrm{a}_0(2)^2}{(2)} \\ & \mathrm{r}=2 \mathrm{a}_0\end{aligned}$
Asked in: JEE Main 2025 (22 Jan Shift 1)
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