Radius of a certain orbit of hydrogen atom is $8.48 Ã…$. If energy of electron in this orbit is $E / x$. then $x=$ _____ (Given $\mathrm{a}_0=0.529 Ã…, E=$ energy of electron in ground state).

Question

Aicharya · Accepted Answer

We know $\begin{aligned} & \mathrm{r}=0.529 \frac{\mathrm{n}^2}{\mathrm{Z}} \Rightarrow 8.48=0.529 \frac{\mathrm{n}^2}{1} \\ & \mathrm{n}^2=16 \Rightarrow \mathrm{n}=4 \end{aligned}$
We know $\mathrm{E} \propto \frac{1}{\mathrm{n}^2}$ $\begin{aligned} & E_{n^{\text {th }}}=\frac{E}{16} \\ & x=16 \end{aligned}$

Radius of a certain orbit of hydrogen atom is $8.48 Ã…$. If energy of electron in this orbit is $E / x$.…

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