Radiations of two photons having energies twice and five times the work function of metal are incident…

Radiations of two photons having energies twice and five times the work function of metal are incident successively on metal surface. The ratio of the maximum velocity of photo electrons emitted in the two cases will be
  1. $1: 1$
  2. $1: 2$
  3. $1: 3$
  4. $1: 4$

Solution

\(\begin{aligned} & \frac{\frac{1}{2} \mathrm{mv}_{\max 1}^2}{\frac{1}{2} \mathrm{mv}_{\max 2}^2}=\frac{1}{4} \\ & \frac{\mathrm{v}_{\max 1}^2}{\mathrm{v}_{\max 2}^2}=\frac{1}{4} \\ & \frac{\mathrm{v}_{\max 1}}{\mathrm{v}_{\max 2}}=\frac{1}{2}\end{aligned}\) .

Asked in: MHT CET 2023 (12 May Shift 1)

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