Radiation of wavelength λ is incident on a photocell. The fastest emitted photoelectron has a speed v . If…

Radiation of wavelength λ is incident on a photocell. The fastest emitted photoelectron has a speed v. If the wavelength is changed to 3λ4, the speed of the fastest emitted photoelectron will be
  1. =v4312
  2. =v3412
  3. >v4312
  4. <v4312

Solution

12mv2=hcλ-ϕ ...(i)

12mv'2=43hcλ-ϕ  ...(ii)

From Eqn. (i)

hcλ=12mv2+ϕ

On putting this Equation (ii)

12mv2=4312mv2+ϕ-ϕ

v'2=43v2+2ϕ3m

v'>43v

Asked in: JEE Main 2016 (03 Apr)

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