Pure silicon at 300 K has equal electron and hole concentration of $1.5 \times 10^{16} \mathrm{~m}^{-3}$. If…

Pure silicon at 300 K has equal electron and hole concentration of $1.5 \times 10^{16} \mathrm{~m}^{-3}$. If the hole concentration increases to $3 \times 10^{22} \mathrm{~m}^{-3}$, then electron concentration in the silicon is
  1. $0.75 \times 10^9 \mathrm{~m}^{-3}$
  2. $750 \mathrm{~m}^{-3}$
  3. $75 \mathrm{~m}^{-3}$
  4. $7.5 \times 10^9 \mathrm{~m}^{-3}$

Solution

$\mathrm{n}_{\mathrm{e}}=\mathrm{n}_{\mathrm{h}}=1.5 \times 10^{16} \mathrm{~m}^{-3}$ $\therefore \quad$ Number of intrinsic charge carriers, $\mathrm{n}_{\mathrm{i}}^2=\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}}=\left(1.5 \times 10^{16}\right)^2$
Again, $\begin{aligned} & \left(1.5 \times 10^{16}\right)^2=\mathrm{n}_{\mathrm{e}}\left(3 \times 10^{22}\right) \\ & \therefore \quad \mathrm{n}_{\mathrm{e}}=7.5 \times 10^9 \mathrm{~m}^{-3} \end{aligned}$

Asked in: AP EAMCET 2024 (21 May Shift 2)

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