Prussian blue is formed when

Prussian blue is formed when
  1. ferrous sulphate reacts with $\mathrm{FeCl}_{3}$
  2. ferric sulphate reacts with $\mathrm{K}_{4} \mathrm{Fe}(\mathrm{CN})_{6}$
  3. ferrous ammonium sulphate reacts with $\mathrm{FeCl}_{3}$
  4. ammonium sulphate reacts with $\mathrm{NO}_{2}$

Solution

$2 \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}ight)_{3}+3 \mathrm{~K}_{4}\left[\left(\mathrm{Fe}(\mathrm{CN})_{6}ight] ightarrowight.$
$\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}ight]_{3}+6 \mathrm{~K}_{2} \mathrm{SO}_{4}$
prussian blue .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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