Propyne reacts with $\mathrm{HBr}$ to form Ethe compound $\mathrm{Z}$ is

Propyne reacts with $\mathrm{HBr}$ to form Ethe compound $\mathrm{Z}$ is
  1. $\mathrm{CH}_2(\mathrm{Br}) \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}$
  2. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHBr}_2$
  3. $\mathrm{CH}_3 \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_2 \mathrm{Br}$
  4. $\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3$

Solution


This is the electrophilic addition so the product will be 2,2 - dibromo propane.

Asked in: AP EAMCET 2018 (23 Apr Shift 2)

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