Propionic acid with $\mathrm{Br}_2 / \mathrm{P}$ yields a dibromo product, Its structure would be -

Propionic acid with $\mathrm{Br}_2 / \mathrm{P}$ yields a dibromo product, Its structure would be -

  1. $\mathrm{CH}_2 \mathrm{Br}-\mathrm{CHBr}-\mathrm{COOH}$

  2. $\mathrm{CH}_2 \mathrm{Br}-\mathrm{CH}_2-\mathrm{COBr}$

Asked in: NEET 2009 (Mains)

Practice more Halogen Derivatives questions on Aicharya