Prong of a vibrating tuning fork is in contact with water surface. It produces concentric circular waves on the surface of water. The distance between five consecutive crests is 0.8 m and the velocity of wave on the water surface is $56 \mathrm{~m} / \mathrm{s}$. The frequency of tuning fork is

Question

Aicharya · Accepted Answer

$\begin{aligned} & \lambda=\frac{	ext { Distance between crests }}{	ext { No.of crest }-1}=\frac{0.8}{4}=0.2 \mathrm{~m} \ & \mathrm{v}=\mathrm{n} \lambda \quad \Rightarrow \mathrm{n}=\frac{\mathrm{v}}{\lambda} \ 	herefore \quad & \mathrm{n}=\frac{56}{0.2}=280 \mathrm{~Hz}\end{aligned}$

Prong of a vibrating tuning fork is in contact with water surface. It produces concentric circular waves on…

Solution