Product of two rationals is $\dfrac{4}{9}$ and one is $\dfrac{2}{3}$. The other is

Product of two rationals is $\dfrac{4}{9}$ and one is $\dfrac{2}{3}$. The other is
  1. $\dfrac{2}{3}$
  2. $\dfrac{4}{6}$
  3. $\dfrac{8}{27}$
  4. $\dfrac{3}{2}$

Solution

$\dfrac{4}{9} \div \dfrac{2}{3} = \dfrac{2}{3}$.

Asked in: IMO

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