Preparation of potassium permanganate from $\mathrm{MnO}_2$ involves two step process in which the 1st step…
- $\mathrm{K}_3 \mathrm{MnO}_4$
- $\mathrm{K}_4\left[\mathrm{Mn}(\mathrm{OH})_6\right]$
- $\mathrm{KMnO}_4$
- $\mathrm{K}_2 \mathrm{MnO}_4$
Solution
$\mathrm{MnO}_2 \xrightarrow[\mathrm{KNO}_3]{\mathrm{KOH}} \mathrm{K}_2 \mathrm{MnO}_4 \xrightarrow[\substack{\text { Oxidation in } \\ \text { Alkaline solution }}]{\text { Elecrolta }} \mathrm{KMnO}_4$
Asked in: JEE Main 2025 (24 Jan Shift 1)