Predict the correct intermediate and product in the following reaction $\begin{aligned} &H_{3}C-C \equiv CH…

1. $\begin{array}{cc}\text{A : }{\text{H}}_3\text{C}-\underset{\underset{{\text{SO}}_4}{\text{|}}}{\text{C}}={\text{CH}}_2& \text{B : }{\text{H}}_3\text{C}-\underset{\underset{\text{O}}{\text{||}}}{\text{C}}-{\text{CH}}_3\end{array}$
2. $\begin{array}{cc}\text{A : }{\text{H}}_3\text{C}-\underset{\underset{\text{OH}}{\text{|}}}{\text{C}}={\text{CH}}_2& \text{B : }{\text{H}}_3\text{C}-\underset{\underset{{\text{SO}}_4}{\text{|}}}{\text{C}}={\text{CH}}_2\end{array}$
3. $\begin{array}{cc}\text{A : }{\text{H}}_3\text{C}-\underset{\underset{\text{O}}{\text{||}}}{\text{C}}-{\text{CH}}_3& \text{B : }{\text{H}}_3\text{C}-\text{C}\equiv \text{CH}\end{array}$
4. $\begin{array}{cc}\text{A : }{\text{H}}_3\text{C}-\underset{\underset{\text{OH}}{\text{|}}}{\text{C}}={\text{CH}}_2& \text{B : }{\text{H}}_3\text{C}-\underset{\underset{\text{O}}{\text{||}}}{\text{C}}-{\text{CH}}_3\end{array}$

Solution

$\mathrm{A}=$prop-1-en-2-ol , $\mathrm{B}=$Acetone

Asked in: NEET 2017

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