Power radiated by a black body at temperature $T_1$ is $P$ and it radiates maximum energy at a wavelength $\lambda_1$. If the temperature of the black body is changed from $T_1$ to $T_2$, it radiates maximum energy at a wavelength $\frac{\lambda_1}{2}$. The power radiated at $T_2$ is

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Aicharya · Accepted Answer

We have, $P \propto T^4 \propto \frac{1}{\lambda^4} \Rightarrow \frac{P_1}{P_2}=\left(\frac{\lambda_2}{\lambda_1}ight)^4$ $\begin{aligned} \frac{P_1}{P_2} & =\frac{1}{16} \ P_2 & =16 P_1=16 P\end{aligned}$

Power radiated by a black body at temperature $T_1$ is $P$ and it radiates maximum energy at a wavelength…

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