Position of an ant ( S in metres) moving in Y - Z plane is given by S = 2 t 2 j ^ + 5 k ^ (where t is in…

Position of an ant ( S in metres) moving in Y-Z plane is given by S=2t2j^+5k^ (where t is in second). The magnitude and direction of velocity of the ant at t=1 s will be :

  1. 16 m s-1 in y-direction
  2. 4 m s-1 in x-direction
  3. 9 m s-1 in z-direction
  4. 4 m s-1 in y-direction

Solution

The velocity of the ant can be found as follows:

v→=dS→dt=ddt2t2j^+5k^=4tj^   ...1

At t=1 s, from equation (1), it follows that

v→=4j^

Asked in: JEE Main 2024 (27 Jan Shift 1)

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