Poly dispersity index of a polymer is 1.25 If $\overline{\mathrm{M}}_{\mathrm{n}}$ is 800 , what is its…
Poly dispersity index of a polymer is 1.25 If $\overline{\mathrm{M}}_{\mathrm{n}}$ is 800 , what is its $\overline{\mathrm{M}}_{\mathrm{w}}$ ?
- $800$
- $900$
- $950$
- $1000$
Solution
$\mathrm{PDI}=\frac{\overline{\mathrm{M}}_{\mathrm{W}}}{\overline{\mathrm{M}}_{\mathrm{n}}}=1.25$ (given)
$\overline{\mathrm{M}}_{\mathrm{n}}=800 \Rightarrow \overline{\mathrm{M}}_{\mathrm{W}}=800 \times 1.25=1000$
Asked in: AP EAMCET 2023 (16 May Shift 2)
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